The pd supply in the flashgun for a camera is 1.4 V. When the gun fires, a charge of 890 mC flows through the bulb. Calculate the energy released.
| Data statements | V = 1.4 V Q = 0.89 C |
Q = 890 x 10-3 C |
| Formula | E = Q V | |
| Transposition | (not needed) | |
| Substitution | E = 1.4 V x 0.89 C | |
| Evaluation | E = 1.2 J | 1.246 has to be reduced to 2 SF, controlled by the pd datum. |