Calculate the mass of gold in a bar of volume 240 cm3 . The density of gold is 19300 kg/m3
| Data statements | V = 240 x 10-6 m3 r = 19300 kg/m3 |
Translating the c and applying the cube
to the whole of cm gives
240 x (10-2 m)3
|
| Formula | r = m / V | |
| Transposition | m = r V | |
| Substitution | m = 19300 kg/m3 x 240 x 10-6 m3 | |
| Evaluation | m = 4.6 kg | 4.632 has to be reduced to 2 SF, controlled by the volume datum. This one is tricky, because neither datum is clear about how many sig figs there are. |